y^2+9y-16=0

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Solution for y^2+9y-16=0 equation: 



y^2+9y-16=0

a = 1; b = 9; c = -16;
Δ = b2-4ac
Δ = 92-4·1·(-16)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{145}}{2*1}=\frac{-9-\sqrt{145}}{2}
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{145}}{2*1}=\frac{-9+\sqrt{145}}{2}
$

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